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  2. The water potential of the potato cells would decrease. The molar concentration of the potato cells is moles/liter, thus if the potato becomes dehydrated the solute concentration would increase causing the solute potential, and in turn the water potential, to decrease.
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  5. The water potential inside the bag is -9.84 bars and the water potential outside the bag is -2.46 bars.
  6. Ѱ = - i CRT = - (1)(.4 M)(.0831 liter bars/mole K)(273 + 23 K)
  7. Ѱ = - i CRT = - (1)(.1 M)(.0831 liter bars/mole K)(273 + 23 K)
  8. Water will diffuse into the bag, because the water potential outside the bag is greater, and water moves from a higher water potential to a lower water potential.
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  11. The molar concentration of solutes within the zucchini cells is .358 M calculated by a line of best fit.
  12. The water potential of the zucchini cores is -8.925 bars.
  13. Ѱ = - i CRT = - (1)(.358 M)(.0831 liter bars/mole K)(273 + 27 K)
  14. Ѱ = -8.925 bars
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  17. The distilled water would have a higher concentration of water molecules.
  18. The distilled water would have a higher water potential.
  19. The red blood cell would expand and lyse because water would move into it from its surroundings due to its lower water potential and higher solute concentration.
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